[文本处理] bat 截取字符串中逗号前后两个子字符串

fengyuyi

一个字符串str=“123456,abcd”
请问怎么能得到两个子字符串
str1=123456
str2=abcd
请问应该怎么编码？

DAIC

@echo off
set str="123456,abcd"
for /f "tokens=1-2 delims=," %%i in ("%str%") do (
    set str1=%%i
    set str2=%%j
)
echo,%str1%
echo,%str2%
pause
复制代码

xxpinqz

    set str1=123456
    set str2=abcd
复制代码

    set "str1=%%i"
    set "str2=%%j"
复制代码

写顺手了吧～～

fengyuyi

谢谢，2楼的和3楼的。

c755731262

@echo off&color f0
set str=“123456,abcd”
set str=%str:“=%
set str=%str:”=%
for /f "tokens=1,2 delims=," %%i in ("%str%") do (
set str1=%%i
set str2=%%j
)
echo str1=%str1% str2=%str2%
pause
复制代码

回复 1# fengyuyi

c755731262

@echo off&color f0
set str=“123456,abcd”
set str1=%str:~1,6%
set str2=%str:~8,-1%
echo %str1% %str2%
pause
复制代码

回复 1# fengyuyi