[问题求助] [己解决]Python如何读取文本数？

keshun

1.txt内容：
A:XRP  B:-36.15%  C:0.1866  D:-32.39%  E:-59.08%  F:0.41%  G:-33.01%

with open("1.txt", "r") as f:
    msg = f.readlines()[0]
print(msg)
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请教！代码读取1.txt显示'C','F'两组数。
print(C)  #显示0.1866
print(F)  #显示0.41%

Gin_Q

回复 1# keshun


    你的文本格式是否如你所说，是否统一一致

>>> a
		    
'A:XRP  B:-36.15%  C:0.1866  D:-32.39%  E:-59.08%  F:0.41%  G:-33.01%'
>>> b=a.split()
		    
>>> b[2].split(':')
		    
['C', '0.1866']
>>> b[5].split(':')
		    
['F', '0.41%']
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>>> a
'A:XRP  B:-36.15%  C:0.1866  D:-32.39%  E:-59.08%  F:0.41%  G:-33.01%'
>>> d=re.compile('[CF]:(\d+.?\d+%?)')
>>> d.findall(a)
['0.1866', '0.41%']
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netdzb

回复 2# ivor


代码通不过啊

msg = '''A:XRP  B:-36.15%  C:0.1866  D:-32.39%  E:-59.08%  F:0.41%  G:-33.01%'''

my_d = {}
for i in msg:
    my_d[i.split(':')[0]]=i.split(':')[1]
print(my_d['C'])
print(my_d['F'])

======

my_d[i.split(':')[0]]=i.split(':')[1]这行报错了。

ivor

with open("1.txt", "r") as f:
    msg = f.readlines()[0].split()
    my_d = {}
    for i in msg:
        my_d[i.split(':')[0]]=i.split(':')[1]
print(my_d['C'])
print(my_d['F'])
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