[文本处理] 批处理如何只取一个文本中想要的段？

hijackle

有以下一系列类似文本内容如下：
id=123214214
Name=aaaaaa

id=123214321
Name=gsdagdsg

id=12321421
Name=bbbbbbb

如何屏蔽name=aaaaaa和bbbbbb的这2个小段包括他之前的id=内容，只取除此之外的小段的id和name的值，注意name=aaaaaa和name=bbbbbb这样的小段不一定每个文本都有的，如果有的话name=aaaaaa和name=bbbbbbb是固定的

Hello123World

@echo off
For /f "delims=" %%i in ('dir  /b *.txt') do  findstr /v "Name=bbbbbbb id=12321421 id=123214214 Name=aaaaaa" "%%i">>"%%~nih%%~xi"
pause
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CUer

gawk -v RS= "$0!~/Name=aaaaaa/&&$0!~/Name=bbbbbb/" a.txt
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ArdentMan

@Echo Off&SetLocal EnableDelayedExpansion
For %%a In (*.txt) Do (
  Set "Str="
  (For /F "delims=" %%b In ('Type "%%a"^&Echo end') Do (
    For %%c IN (aaaaaa bbbbb) Do If "%%b" EQU "Name=%%c" Set "Str="
    If Defined Str Echo !Str!&Echo %%b
    Set "Str=%%b"
  )>tem
  Move tem "%%a"
)
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lvsehuaxue

3楼可简化

@echo off&setlocal enabledelayedexpansion
for /f "delims=" %%i in (a.txt) do set %%i&set /a n=n%%2+1&if !n!==2 echo %%i|findstr "aaaaaa bbbbbbb">nul||(echo id=!id!&echo Name=!Name!)   
pause
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lvsehuaxue

@echo off&setlocal enabledelayedexpansion
for /f "delims=" %%i in (a.txt) do (
    set /a n=n%%2+1
    set a=!b!
    set b=%%i  
    if !n!==2 (
      echo !b!|findstr "Name=aaaaaa Name=bbbbbbb">nul || (echo !a!&echo !b!)
    )
) 
pause
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hijackle

只要等号后面的值

601997526

想到一个笨办法，但前提是格式都要跟LZ贴出来的是一样的

@echo off&setlocal ENABLEDELAYEDEXPANSION
for /f %%i in (a.txt) do (set %%i
echo.%%i|findstr /i "^name=">nul&&if "!name!"=="aaaaaa" (echo.>nul) else (if not "!name!"=="bbbbbbb" echo id=!id!&echo name=!name!))
pause
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mxxcgzxxx

是取整段还是只要=号后的值？