alick

也感谢qixiaobin0715的回复

alick

回复 2# flashercs

感谢flashercs的帮助，完美实现想要的结果

qixiaobin0715

刚才代码有点小错误，已重新修订。

qixiaobin0715

回复 1# alick
你应当说明最终要实现什么目的，我觉得直接修改aaa.bat即可：

set /p filename=<list.txt
for /f "delims=" %%a in ('dir /b /s /a-d goto3\bbb.exe') do ren "%%a" "%filename%.exe"
for /f "delims=" %%i in ('dir /b /s /a-d goto3\%filename%.exe') do ...
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实际上用一个for循环也可以定位重命名后的exe文件：

set /p filename=<list.txt
for /f "delims=" %%a in ('dir /b /s /a-d goto3\bbb.exe') do (
ren "%%a" "%filename%.exe"
echo,%%~dpa%filename%.exe
)
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flashercs

<#*,:&cls
@echo off
pushd "%~dp0"
powershell -NoProfile -ExecutionPolicy RemoteSigned -Command ". ([ScriptBlock]::Create((Get-Content -LiteralPath \"%~0\" -ReadCount 0 | Out-String ))) "
popd
pause
exit /b
#>
$txt = "list.txt"
$bbb = "bbb.exe"
$aaa = "aaa.bat"

$arr1 = Get-Content -Path $txt -ReadCount 0
$goto3 = $arr1[0] + ".exe"
foreach ($item in Convert-Path -Path ".\$($arr1[0])\*\*\$bbb") {
  Rename-Item -Path $item -NewName $goto3 -Force
}
$arr2 = Get-Content -Path $aaa -ReadCount 0
$arr2 -replace 'XXX\.exe', $goto3 | Set-Content -Path $aaa
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