[文本处理] 这段文本应该怎么用批处理替换呢？

zhouyao800

a.txt  为以下：
/cntrl_3541_1_828631825
/bk_3541_1_8286318334
/bk_3541_1_828631826
/al_3541_1_828631826
/cntrl_3541_1_828631824
/bk_3541_1_8286318333
/bk_3541_1_8286318262
/al_3541_1_82863182611

b.txt为以下：
chmod 666 $RMAN_LOG_FILE
echo Script $0 >> $RMAN_LOG_FILE
echo ==== started on `date` ==== >> $RMAN_LOG_FILE
echo >> $RMAN_LOG_FILE
ORACLE_HOME=/oracle/product/10.2.0
export ORACLE_HOME
ORACLE_SID=tjtsyw
export ORACLE_SID
ORACLE_USER=oracle
TARGET_CONNECT_STR=sys/Abcd1234
RMAN=$ORACLE_HOME/bin/rman
echo >> $RMAN_LOG_FILE
echo   "RMAN: $RMAN" >> $RMAN_LOG_FILE
echo   "ORACLE_SID: $ORACLE_SID" >> $RMAN_LOG_FILE
echo   "ORACLE_USER: $ORACLE_USER" >> $RMAN_LOG_FILE
echo   "ORACLE_HOME: $ORACLE_HOME" >> $RMAN_LOG_FILE
CMD_STR="
ORACLE_HOME=$ORACLE_HOME
export ORACLE_HOME
ORACLE_SID=$ORACLE_SID
export ORACLE_SID
$RMAN target $TARGET_CONNECT_STR nocatalog msglog $RMAN_LOG_FILE append << EOF
RUN {
     shutdown immediate;
     startup nomount;
     allocate channel ch00 type 'sbt_tape';
     send 'NB_ORA_CLIENT=tjtsyw1';
     send 'NB_ORA_SERV=NBUserver';
     restore controlfile from '/cntrl_3541_1_828631826';
     release channel ch00;
     alter database mount;
     
编写什么样的批处理能实现把a.txt中的第一行复制出来 替换b.txt中restore controlfile from '/cntrl_3541_1_828631826'这句话中from后面单引号里面的内容呢？替换完了生成c.txt

Lumiere

回复 1# zhouyao800


    看不出来你这个批处理有何意义

tmplinshi

@echo off
setlocal

set listFile="a.txt"
set inFile="b.txt"
set outFile="c.txt"

set /p Line1=<%listFile%

(
	for /f "tokens=*" %%a in (' findstr /n .* %inFile% ') do (
		set ThisLine=%%a
		
		setlocal enabledelayedexpansion
		
		if "!ThisLine:restore controlfile from '=!" neq "!ThisLine!" (
			for /f "delims='" %%a in ("!ThisLine!") do (
				set ThisLine=%%a'!Line1!';
			)
		)
		echo,!ThisLine:*:=!
		
		endlocal
	)
) >%outFile%
复制代码

或者用 sed:

set /p Line1=<a.txt
sed -r "s|(restore controlfile from )'[^']+'|\1'%Line1%'|ig" b.txt >c.txt
复制代码