[文本处理] [已解决]求解批处理显示出两列并将第二列内容平均分到第一列

openye0521

批处理显示出两列并将第二列内容平均分到第一列
192.168.1.0  192.168.50.1
192.168.1.1  192.168.50.1
192.168.1.2  192.168.50.2
192.168.1.3  192.168.50.2
192.168.1.4  192.168.50.3
192.168.1.5  192.168.50.3
192.168.1.6  192.168.50.4
192.168.1.7  192.168.50.4
192.168.1.8  192.168.50.5
192.168.1.9  192.168.50.5

for /l %i in (0 1 10) do echo 192.168.1.%i
     for /l%a (1 1 5) do echo 192.168..%a

openye0521

非常感谢已解决

回家路上

回复 3# openye0521

@for /l %%i in (0 1 9) do @echo;192.168.1.%%i  192.168.50.2
@pause
复制代码

openye0521

非常感谢 思路清晰  在请教下这样的话 直接使用FOR/l 怎么列出来
192.168.1.0  192.168.50.2
192.168.1.1  192.168.50.2
192.168.1.2  192.168.50.2
192.168.1.3  192.168.50.2
192.168.1.4  192.168.50.2
192.168.1.5  192.168.50.2
192.168.1.6  192.168.50.2
192.168.1.7  192.168.50.2
192.168.1.8  192.168.50.2
192.168.1.9  192.168.50.2

回家路上

@echo off & setlocal enabledelayedexpansion
set i=9
set j=5
set /a "d=(%i%+1)/%j%+^!^!((%i%+1)%%%j%)"
for /l %%i in (0 1 %i%)do (
	set /a x=%%i/%d%+1
	echo;192.168.0.%%i    192.168.50.!x!
)
pause & exit /b
复制代码

@echo off & setlocal enabledelayedexpansion
set i=9
set j=5
for /l %%i in (0 1 %i%)do (
	set /a x=%%i%%%j%+1
	echo;192.168.0.%%i    192.168.50.!x!
)
pause & exit /b
复制代码