[文本处理] 批处理set变量失败，这是因为什么

hentai87

@echo off
pushd "%~dp0"

for /f "delims=:" %%a in ('findstr /n msmg设置 ..\set.txt') do set n=%%a
	for /f "skip=%n% delims=" %%b in (..\set.txt) do (
set dism=%%b\Bin\x64\DISM10\dism.exe
echo %dism%
)

pause
复制代码

结果
ECHO is off.
Press any key to continue . . .

但是这样就成功了
set var=我是值
echo %var%

是无法set %%b吗

Batcher

回复 1# hentai87

@echo off
setlocal enabledelayedexpansion
pushd "%~dp0"
for /f "delims=:" %%a in ('findstr /n msmg设置 ..\set.txt') do (
    call :GetDISM %%a
)
pause
goto :eof

:GetDISM
for /f "skip=%1 delims=" %%b in (..\set.txt) do (
    set "dism=%%b\Bin\x64\DISM10\dism.exe"
    echo,!dism!
)
复制代码

flashercs

@echo off
pushd "%~dp0"

for /f "delims=:" %%a in ('findstr /n msmg设置 ..\set.txt') do set n=%%a
	for /f "skip=%n% delims=" %%b in (..\set.txt) do (
set dism=%%b\Bin\x64\DISM10\dism.exe
)
echo %dism%
pause
复制代码

cmd命令行的括号()中的所有语句等同于一行代码,而cmd执行每一行语句前要给该行代码的所有变量进行预赋值,此时%dism%还是空值,所以echo %dism%等同于echo 空白.

hentai87

回复 2# smss


    setlocal EnableDelayedExpansion

D:\lopatkin\Package_Remover\Remove-package>for /F "delims=:" %a in ('findstr /n msmg设置 ..\set.txt') do set n=%a

D:\lopatkin\Package_Remover\Remove-package>set n=2

D:\lopatkin\Package_Remover\Remove-package>for /F "skip=2 delims=" %b in (..\set.txt) do (
set dism=%b\Bin\x64\DISM10\dism.exe
echo
)

D:\lopatkin\Package_Remover\Remove-package>(
set dism=D:\ZT\ToolKit_v9.9\Bin\x64\DISM10\dism.exe
echo
)
ECHO is on.


还是这样

smss

加延迟变量试试
复制代码