powershell -c "((gc .\1.txt) -replace '[ ]+(?=[\S])',',') -replace '[ ]+$',''>2.txt"
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@echo off
del /q 2.txt>nul 2>nul
echo 展示需要的列的位置，缺点只有26列。 源 1.txt 结果 2.txt
echo 用法，根据结果明确每列对应的变量名称，复制下面源码，修改保留对应列，调整顺序，变更间隔符。
echo 建议先取文件部分内容用于观察。
pause
for /f "tokens=1-26 delims= " %%a in (1.txt) do echo A%%a B%%b C%%c D%%d E%%e F%%f G%%g H%%h I%%i J%%j K%%k L%%l M%%m N%%n O%%o P%%p Q%%q R%%r S%%s T%%t U%%u V%%v W%%w X%%x Y%%y Z%%z>>2.txt
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@echo off
(for /f "useback delims=" %%a in (`find /n /v "" ^<"1.txt"`) do (
	set "str=%%a "
	setlocal enabledelayedexpansion
	for /l %%l in (1,1,10) do (
		set "str=!str:  = !"
	)
	set "str=!str: =,!"
	set "str=!str:~0,-1!"
	echo=!str:*]=!
	endlocal
))>"2.txt"
pause
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@echo off &setlocal enabledelayedexpansion
(for /f "delims=" %%a in (源文件.txt) do (
	set "_str=" &for %%b in (%%a) do (set "_str=!_str!,%%b")
	echo,!_str:~1!
))>新文件.txt
endlocal &exit/b
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gawk -v"OFS=," "$1=$1" 1.txt>2.txt
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