标题: [文本处理] BAT如何排列通话时长? [打印本页]
作者: 非常感谢 时间: 2013-8-3 15:44 标题: BAT如何排列通话时长?
通话时长
00:04:25
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合计: 04:02:25
上面的通话时间长短不一,想要由长到短从新排列一下。是否可行?(里面有通话时长一样的都要保留,请不要过滤) 谢谢!
作者: batman 时间: 2013-8-3 15:55
sort /r a.txt
作者: 非常感谢 时间: 2013-8-3 16:09
您好batman,测试了一下没变化呀。 请帮忙修正一下,谢谢!
作者: CrLf 时间: 2013-8-3 17:54
本帖最后由 CrLf 于 2013-8-3 17:58 编辑
回复 3# 非常感谢
你是要输出到文件吧,那就写成这样:复制代码
如果要保留原有格式,就这样:- @(echo 通话时长
- findstr /b [0-9] a.txt|sort /r
- find "合计"<a.txt)>b.txt
- move /y b.txt a.txt
复制代码
作者: 非常感谢 时间: 2013-8-3 19:14
我想把两个代码合在一起用怎么写?顺序是
第一个代码:
@echo off&setlocal enabledelayedexpansion
(for /f "tokens=7delims=;" %%a in (a.txt) do (
echo %%a
for /f "tokens=1-3delims=:" %%i in ("%%a") do (
set/a h+=1%%i%%100,m+=1%%j%%100,s+=1%%k%%100
)
)
set/a m+=s/60,s=s%%60+100,h+=m/60,m=m%%60+100
if !h! lss 10 set h=0!h!
echo 合计: !h!:!m:~-2!:!s:~-2!
)>b.txt
start b.txt
第二个代码:
@sort /r a.txt /o a.txt
作者: weichenxiehou 时间: 2013-8-4 09:14
回复 5# 非常感谢 - @echo off&setlocal enabledelayedexpansion
- (for /f "tokens=7delims=;" %%a in (a.txt) do (
- echo %%a
- for /f "tokens=1-3delims=:" %%i in ("%%a") do (
- set/a h+=1%%i%%100,m+=1%%j%%100,s+=1%%k%%100
- )
- )
- set/a m+=s/60,s=s%%60+100,h+=m/60,m=m%%60+100
- if !h! lss 10 set h=0!h!
- echo 合计: !h!:!m:~-2!:!s:~-2!
- )>b.txt
- sort /r b.txt /o b.txt
- start b.txt
复制代码
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