[文本处理] 【已解决】BAT：如何在指定位置插入字符

思想之翼

D:\DATA\1.txt记录格式为：
123=000 001=124=003 005 006=125=007
123=000 001=124=003 005 006=125=007
...
123=000=124=003 006=125=007

如何在所有行的第2 4 6 8...个“=”右侧，插入“=”？

结果为：
123=000 001==124=003 005 006==125=007
123=000 001==124=003 005 006==125=007
...
123=000==124=003 006==125=007

pd1

'123=000 001=124=003 005 006=125=007
123=000 001=124=003 005 006=125=007
...
123=000=124=003 006=125=007' -replace '=(.*?)=','=$1=='
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77七

@echo off
(for /f "useback delims=" %%x in ("D:\DATA\1.txt") do (
	setlocal
	call :1 "%%x"
	endlocal
))>"D:\DATA\2.txt"
pause & exit

	:1
	for /f "tokens=1* delims==" %%a in ("%~1") do (
		set str=%str%%%a=%m%
		if "%%b" neq "" (
			if defined m (
				set m=
			) else (
				set m==
			)
			call :1 "%%b"
		) else (
			echo %str%%%a
			exit /b
		)
	)
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Five66

不知行否，记录内容最好不要有特殊字符
会在当前目录生成新文件2.txt
已编辑

@echo off

set "fpath=D:\DATA\1.txt"

(for /f "usebackq delims=" %%i in ("%fpath%") do (
set "str=%%i"
setlocal enabledelayedexpansion
set str2=!str: =$#$!
set n=0
for %%a in (!str2!) do (
set /a n+=1,m=n%%2
if !m! equ 0 (
set "str3=!str3!%%a=="
) else (
set "str3=!str3!%%a="
)
)
if !m! equ 0 (
set str3=!str3:~0,-2!
) else (
set str3=!str3:~0,-1!
)
echo=!str3:$#$= !
endlocal
))>2.txt

pause
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