[问题求助] 大佬们，Linux shell sed代码替换求助

smdx

各位大佬好，Linux shell sed代码替换求助，请问如何用sed命令替换代码？

想实现把代码的
a=$(ip address | grep ^[0-9] | awk -F: '{print $2}' | sed "s/ //g" | grep '^[e]' | grep -v "@" | grep -v "\.")
替换成
a=$(ip address | grep ^[0-9] | awk -F: '{print $2}' | sed "s/ //g" | grep '^eth' | awk -F"@" '{print $1}')

命令用于GitHub Actions云编译openwrt固件sh脚本，请问要怎么做？谢谢


ethinfo原代码：

#!/bin/sh
a=$(ip address | grep ^[0-9] | awk -F: '{print $2}' | sed "s/ //g" | grep '^[e]' | grep -v "@" | grep -v "\.")
b=$(echo "$a" | wc -l)
rm -f /tmp/state/ethinfo
 
echo -n "[" > /tmp/state/ethinfo
 
for i in $(seq 1 $b)
do
	h=$(echo '{"name":' )
	c=$(echo "$a" | sed -n ${i}p)
	d=$(ethtool $c)
 
	e=$(echo "$d" | grep "Link detected" | awk -F: '{printf $2}' | sed 's/^[ \t]*//g')
	if [ $e = yes ]; then
		l=1
	else
		l=0
	fi
 
	f=$(echo "$d" | grep "Speed" | awk -F: '{printf $2}' | sed 's/^[ \t]*//g' | tr -d "Unknown!")
	[ -z "$f" ] && f=" - "
 
	g=$(echo "$d" | grep "Duplex" | awk -F: '{printf $2}' | sed 's/^[ \t]*//g')
	if [ "$g" == "Full" ]; then
		x=1
	else
		x=0
	fi
 
	echo -n "$h \"$c\", \"status\": $l, \"speed\": \"$f\", \"duplex\": $x}," >> /tmp/state/ethinfo
done
 
sed -i 's/.$//' /tmp/state/ethinfo
 
echo -n "]" >> /tmp/state/ethinfo
 
cat /tmp/state/ethinfoCOPY