[文本处理] 批处理/sed/gawk中如何删除文本中每行里指定字符后的内容？

飞龙project

下面是一个文件（节选），我想删除每行里以？开头的之后的内容

#EXTM3U
#EXT-X-VERSION:3
#EXT-X-TARGETDURATION:20
#EXT-X-MEDIA-SEQUENCE:0
#EXTINF:17.760000,
http://website/hls/junior/3/1CCMN4CC4D-hls0.ts?auth_key=1582255823-0-0-431c012620e68d9
#EXTINF:6.440000,
http://website/hls/junior/3/1CCMN4CC4D-hls1.ts?auth_key=1582255823-0-0-e68d8911766cc47
#EXTINF:10.000000,
http://website/hls/junior/3/1CCMN4CC4D-hls2.ts?auth_key=1582255823-0-0-02a02b662ed0ca8
·········
#EXTINF:6.040000,
http://website/hls/junior/3/1CCMN4CC4D-hls156.ts?auth_key=1582255823-0-0-4143e53286841c
#EXT-X-ENDLIST
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变为：

#EXTM3U
#EXT-X-VERSION:3
#EXT-X-TARGETDURATION:20
#EXT-X-MEDIA-SEQUENCE:0
#EXTINF:17.760000,
1CCMN4CC4D-hls0.ts
#EXTINF:6.440000,
1CCMN4CC4D-hls1.ts
#EXTINF:10.000000,
1CCMN4CC4D-hls2.ts
·········
#EXTINF:6.040000,
1CCMN4CC4D-hls156.ts
#EXT-X-ENDLIST
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其中保留以#开头的内容，谢谢了！

zaqmlp

sed -i "s/\?.*$//" "xx.txt"
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窄口牛

Gin_Q

不支持中文！！！有没有兴趣学下C！

//Dec-C++ 5.11 

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

int max=10240;

FILE *fp(char *p_n,const char *mode);
char *analyze(char *a);

int main(int argc,char *argv[] )
{
	FILE *s_txt;
	FILE *res_txt;
	s_txt=(fp(argv[1],"r"));
	res_txt=(fp(argv[2],"w"));
	char arr[max]="0";
	char *p=arr;
	char temp[max]="0";
	int i;
	while (fgets(temp,max,s_txt)!=NULL)
	{
 		p=analyze(temp);
		fprintf(res_txt,"%s",p);
	}
	fclose(s_txt);
	fclose(res_txt);
	return 0;
}
FILE *fp(char *p_n,const char *mode)
{
	FILE *fp;
	if ((fp = fopen(p_n,mode)) == NULL)
	{
		printf("%s open fail!!",p_n);
		getchar();
		exit(0);
	}
	return fp;
}

char *analyze(char *a)
{
	static char res[1024]="0";
	char *p=res;
	if (a[0]=='#')   
	{
		strcpy(res,a);
		return p;
	}
	char del='/';
	int i,j=0;
	for (i=0;a[i]!='\0';i++)
	{
		if (a[i]==del) j=0;
		if (a[i]!='?' && a[i]!=del) 
		{
			*(p+j)=a[i];
			j++;
		}
		else if (a[i]=='?')
		{
			*(p+j)='\n'; 
			*(p+j+1)='\0';
			return p;
		}

	}
	strcpy(res,a);
	return p;

}
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