[特效代码] 【已解决】批处理怎样实现1-10 顺着排 跟倒着排？

@echo off
set /p n1=user insert num1:
set /p n2=user insert num2:
set /a r=%n2%-1
set t=0
:main
setlocal enabledelayedexpansion
for /l %%a in (1 1 %n1%) do (
set "s=!s!%%a"
set /a t+=1
)
if !t! geq !n2! (set str=!s!) else goto main
for /l %%a in (1 1 %n2%) do set str=!str:~,%%a! & echo !str! &set str=!s!
for /l %%b in (%r% -1 1) do set str=!str:~,%%b! & echo !str! &set str=!s!
pause
复制代码

@Echo Off
SetLocal EnableDelayedExpansion
Set /P Num1=user insert num1:
Set /P Num2=user insert num2:
For /L %%i In (1 1 %Num2%) Do (
	Set N=0
	For /L %%j In (1 1 %%i) Do (
		If "!N!"=="3" (Set N=1) Else Set /A N+=1
		Set .%%i=!.%%i!!N!
	)
	Echo !.%%i!
)
Set /A Num2-=1
For /L %%i In (%Num2% -1 1) Do Echo !.%%i!
复制代码

@echo off&setlocal enabledelayedexpansion
set /p n1=user insert num1:
set /p n2=user insert num2:
:loop
for /l %%a in (1,1,%n1%) do set "s=!s!%%a"
if "!s:~%n2%!" equ "" goto :loop
for /l %%a in (1,1,%n2%) do echo !s:~,%%a!
set/a n2-=1&for /l %%a in (!n2!,-1,1) do echo !s:~,%%a!
pause
复制代码

@Echo Off
SetLocal EnableDelayedExpansion
Set /P Num=user insert Num:
For /L %%i In (1 1 %Num%) Do (
	Set N=0
	For /L %%j In (1 1 %%i) Do (
		If "!N!"=="%Num%" (Set N=1) Else Set /A N+=1
		Set .%%i=!.%%i!!N!
	)
	Echo !.%%i!
)
Set /A Num-=1
For /L %%i In (%Num% -1 1) Do Echo !.%%i!
pause>nul
复制代码

@Echo Off 2>nul 3>nul
SetLocal EnableDelayedExpansion
Set /P Num1=user insert num1:
Set /P Num2=user insert num2:
For /L %%i In (1 1 %Num2%) Do Set /A "1/(N-Num1)"&&Set /A N+=1||Set N=1&Set ..=!..!!N!
For /L %%i In (%Num2% -1 -%Num2%) Do For /F "Delims=-" %%j In ("%%i") Do Set /A "1/%%i"&&Echo;!..:~0,-%%j!||Echo !..!
Pause
复制代码