[日期时间] 批处理怎么在获取的时间上加上几秒？

@echo off
set /p n=请输入要累加的秒数：
>gettime.vbs echo dim t,h,m,s
>>gettime.vbs echo t=Hour(Now)*3600+Minute(Now)*60+Second(Now)+%n%
>>gettime.vbs echo h=t\3600
>>gettime.vbs echo m=(t mod 3600)\60
>>gettime.vbs echo s=(t mod 3600) mod 60
>>gettime.vbs echo if (h^<10) then h="0"^&h
>>gettime.vbs echo if (m^<10) then m="0"^&m
>>gettime.vbs echo if (s^<10) then s="0"^&s
>>gettime.vbs echo wscript.echo h^&":"^&m^&":"^&s
for /f %%a in ('cscript /nologo gettime.vbs') do (set "gtime=%%a")
del gettime.vbs /f /q
echo 当前时间为%time:~0,8%
echo 累加%n%秒后的时间为%gtime%
pause
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<!-- : www.bathome.net
@echo off
for /f "delims=" %%a in ('echo %time:~,8% ^| mshta "file://%~0"') do echo %%a
pause&exit
-->


<script language=vbs>
Set fso = CreateObject("Scripting.FileSystemObject")
t = fso.GetStandardStream(0).ReadAll
t = DateAdd("s",100,CDate(t))
t = Hour(t) & ":" & Right("0" & Minute(t), 2) & ":" & Right("0" & Second(t), 2)
fso.GetStandardStream(1).Write t
close
</script>
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@echo off
set n=5
set t=%time: =0%
set /a s=n+(1%t:~,2%-100)*3600+(1%t:~3,2%-100)*60+1%t:~6,2%-100
set /a hh=s/3600%%24+100,mm=s%%3600/60+100,ss=s%%60+100
set "newTime=%hh:~1%:%mm:~1%:%ss:~1%"
echo,%newTime%
pause
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(Get-Date).AddSeconds(1000) | Get-Date -Format 'hh:mm:ss'
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@if(0)==(0) echo off
CScript -NoLogo -E:JScript %0
pause & exit
@end
var t = new Date(new Date().getTime()+5000);
var reg = /((\d{1,2}:){2}\d{1,2})/g;
t.toLocaleString().replace(reg, function(a,b){WSH.echo(b)});
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