[网络连接] 批处理命令netstat -ano如何判断8001和8002端口？

@echo off
for %%a in (8001 8002) do (
  netstat -ano|findstr "%%a">nul && set "v%%a=1" || set "v%%a=0"
)
if "%v8001%"=="1" (
  if "%v8002%"=="1" (goto :oua) else goto :ouq
) else (
  if "%v8002%"=="1" (goto :ouq) else goto :ouz
)

:oua
echo 端口全部存在&pause&goto :eof
:ouq
echo 仅存在一个端口&pause&goto :eof
:ouz
echo 端口都不存在&pause
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@echo off
for %%a in (8001 8002) do (
  netstat -ano|findstr "%%a">nul && set "v%%a=1" || set "v%%a=0"
)
set/a "ALL=v8001 + v8002"
if "%ALL%"=="2" (goto :5) else goto :qqw

:5
echo 端口全部存在&pause&goto :eof
:qqw
echo 最多存在一个端口&pause&goto :eof
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@echo off & setlocal enabledelayedexpansion
set "Ports=8001 8002"
for %%a in (%Ports% Any) do set "found%%a=0"
set "foundAll=1"
for /f "tokens=3,5 delims=: " %%a in ('netstat -an') do (
  set /a "found%%a=1,found%%b=1"
)

for %%a in (%Ports%) do set /a "foundAll&=found%%a, foundAny|=found%%a"
if "!foundAll!"=="1" (echo,找到全部端口) else (
  for %%a in (%Ports%) do if "!found%%a!"=="1" (echo,找到端口 %%a) else (echo,未找到端口 %%a)
  if "!foundAny!"=="0" (echo,未找到任何端口) else (echo,找到至少一个端口)
)
pause
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